Question : $\frac{\cos \theta}{\sec \theta-1}+\frac{\cos \theta}{\sec \theta+1}$ is equal to :
Option 1: $2 \sec ^2 \theta$
Option 2: $2 \cot ^2 \theta$
Option 3: $2 \cos ^2 \theta$
Option 4: $2 \sin ^2 \theta$
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Correct Answer: $2 \cot ^2 \theta$
Solution : $\frac{\cos \theta}{\sec \theta-1}+\frac{\cos \theta}{\sec \theta+1}$ =$\frac{\cos \theta(\sec \theta+1)}{\sec^2 \theta-1}+\frac{\cos \theta(\sec \theta-1)}{\sec^2 \theta-1}$ =$\frac{1+\cos \theta+1-\cos\theta}{\tan^2\theta}$ =$2\cot^2\theta$ Hence, the correct answer is $2\cot^2\theta$.
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Question : The value of $\frac{\sin\theta-2\sin^{3}\theta}{2\cos^{3}\theta-\cos\theta}$ is equal to:
Option 1: $\sin\theta$
Option 2: $\cos\theta$
Option 3: $\tan\theta$
Option 4: $\cot\theta$
Question : If $5\tan\theta=4$, then $\frac{5\sin\theta-3\cos\theta}{5\sin\theta+2\cos\theta}$ is equal to:
Option 1: $\frac{2}{3}$
Option 2: $\frac{1}{4}$
Option 3: $\frac{1}{6}$
Option 4: $\frac{1}{3}$
Question : What is the value of $\frac{\sin \theta+\cos \theta}{\sin \theta-\cos \theta}+\frac{\sin \theta-\cos \theta}{\sin \theta+\cos \theta}$?
Option 1: $\frac{1}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 2: $2\left(\sin ^2 \theta-\cos ^2 \theta\right)$
Option 3: $\frac{2}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 4: $\sin ^2 \theta-\cos ^2 \theta$
Question : If $\frac{\sin\theta+\cos\theta}{\sin\theta-\cos\theta}=3$, then the value of $\sin^{4}\theta$ is:
Option 1: $\frac{2}{5}$
Option 2: $\frac{1}{5}$
Option 3: $\frac{16}{25}$
Option 4: $\frac{3}{5}$
Question : If $\tan\theta =\frac{3}{4}$, then the value of $\frac{4\sin^{2}\theta–2\cos^{2}\theta}{4\sin^{2}\theta+3\cos^{2}\theta}$ is equal to:
Option 1: $\frac{1}{21}$
Option 2: $\frac{2}{21}$
Option 3: $\frac{4}{21}$
Option 4: $\frac{8}{21}$
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