You have to solve it using vector mathematics. Let O be the intersection point of BE and DC. OA = a vector
OB = b vector
OC = c vector
OD= (a+b)/2
OE = (a+c)/2
BE = OE - OB  ...solve it
DC = OC - OD .... solve it
BE+DE = 3/2 * (c-b)
BC= c-b
Therefore, BE+DC = 3/2* BC...

Dr KN Modi University, Tonk

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