Question : Marks scored by a student in different subjects are given in the table below
Five marks are to be deducted from each subject due to a shortage of attendance. The net average of the mean, median and mode of the marks obtained is_______.
Option 1: 79.33
Option 2: 77.67
Option 3: 82.66
Option 4: 73
Correct Answer: 77.67
Solution : According to the question, 5 marks are deducted from each subject. ⇒ New marks will be:
⇒ Mean = $\frac{50+85+70+75+85}{5}$ = $\frac{365}{5}$ = $73$ Arranging the data in ascending order: 50, 70, 75, 85, 85 ⇒ Median = middle term = 75 Now, Mode = Most occurred value = 85 So, the net average of Mean, Median, and Mode = $\frac{73+75+85}{3}$ = $\frac{233}{3}$ = 77.67 Hence, the correct answer is 77.67.
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Question : Study the given table and answer the question(s) that follow(s). The marks obtained by four students A, B, C, and D in Mathematics, Statistics, and Computers are given in the following table.
Who among the students has ranked first based on the total marks obtained as per the given table?
Option 1: C
Option 2: D
Option 3: B
Option 4: A
Question : Directions: Study the given pattern carefully and select the number that can replace the question mark (?) in it.
Option 1: 194
Option 2: 150
Option 3: 176
Option 4: 188
Question : The following table shows the percentage of marks obtained by five students - V, W, X, Y and Z - in five subjects.
What are the average marks, in percentage, obtained by X?
Option 1: 76.5%
Option 2: 80.5%
Option 3: 82.5%
Option 4: 85.5%
Question : Calculate the mean from the following table.
Option 1: 33.4
Option 2: 32.6
Option 3: 35.8
Option 4: 34.2
Question : Study the given table and answer the question that follows.
The average number of children per family is :
Option 1: 1.47
Option 2: 1.59
Option 3: 1.23
Option 4: 1.72
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