Question : Out of the total toffees, $\frac{1}{10}$ are wasted. 35% of the rest are given to S and $\frac{1}{8}$ of the total are given to N. If the toffees with N are 10 more than the wasted toffees, how many toffees were given to S?
Option 1: 126
Option 2: 150
Option 3: 110
Option 4: 135
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Correct Answer: 126
Solution : Let the number of toffees be $x$. $\frac{1}{10}$th of them are wasted. Remaining toffees $ = \frac{9}{10}x$ Number of toffees given to S = $\frac{35}{100} \times\frac{9}{10}x = \frac{63}{200}x$ Number of toffees given to N = $\frac{1}{8}x$ According to the question, $\frac{1}{8}x = 10 + \frac{1}{10}x$ ⇒$\frac{1}{8}x-\frac{1}{10}x=10$ ⇒$\frac{5x–4x}{40}=10$ ⇒$x = 400$ Number of toffees given to S = $\frac{63}{200} \times 400 = 126$ Hence, the correct answer is 126.
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Question : Find the sum of $\left (1-\frac{1}{n+1} \right) + \left (1-\frac{2}{n+1} \right) + \left (1- \frac{3}{n+1} \right)+.....\left ( 1- \frac{n}{n+1} \right)$.
Option 1: $n$
Option 2: $\frac{n}{2}$
Option 3: $(n+1)$
Option 4: $\frac{(n+1)}{2}$
Question : A person can hit a target 5 times out of 8 shots. If he fires 10 shots, what is the probability that he will hit the target twice?
Option 1: $\frac{1135 \times 3^8}{8^{10}}$
Option 2: $\frac{1165 \times 3^8}{8^{10}}$
Option 3: $\frac{1175 \times 3^8}{8^{10}}$
Option 4: $\frac{1125 \times 3^8}{8^{10}}$
Question : The ratio of Ram's age to Rahim's age is $10:11$. What is Rahim's age in percentage of Ram's age?
Option 1: $109\frac{1}{2}$%
Option 2: $110$%
Option 3: $111\frac{1}{9}$%
Option 4: $111$%
Question : A and B have some toffees. If A gives one toffee to B, they will have an equal number of toffees. If B gives one toffee to A, the number of toffees with A is double the number with B. The total number of toffees with A and B is:
Option 1: 12
Option 2: 10
Option 3: 14
Option 4: 15
Question : The value of $\frac{1}{(p-n)(n-q)}+\frac{1}{(n-q)(q-p)}+\frac{1}{(q-p)(p-n)}$ is:
Option 1: $1$
Option 2: $0$
Option 3: $p + q + n$
Option 4: $\frac{2n}{p+q}$
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