999 Views

piezoelectric x-cut crystal has thickness 0.002 m. if velocity of sound wave in crystal is 5750 m/sec. calculate the Fundamental frequency of crystal.


Recommended : Get important details about Saveetha Engineering College, Chennai. Download Brochure
Shiv 7th May, 2021
Answer (1)
Rohit K Bhat 16th Jun, 2021

Hello dear aspirant

Given that: Thickness = 0.002 m & Velocity = 5750 m/s

We know that: Velocity = Frequency × Length

5750 = f × 0.0002

f = 5750 / 0.002

f = 2.875 × 10^6 Hz

Therefore, the fundamental frequency of the sound wave in the crystal is 2.875 × 10^6 Hertz.

Hope this helps!!

All the best for your future endeavours



Compare Colleges

College Comparison based on Courses, Placement, Rank, Fee

Compare Now

Know More About

Related Questions

UPES B.Tech Admissions 2026
Apply
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
Presidency University MBA Adm...
Apply
NAAC A+ Accredited | Highest CTC 10 LPA | Top Recruiters : Amazon, Accenture, KPMG, EY, Capgemini & many more
UPES M.Tech Admissions 2026
Apply
Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed 91% Placement, 800+ Recruiters
UPES | BBA Admissions 2026
Apply
#36 in NIRF, NAAC ‘A’ Grade | 100% Placement, up to 30% meritorious scholarships
UPES B.Des Admissions 2026
Apply
Ranked #45 amongst Universities in India by NIRF | Ranked #1 in Academic Reputation in India by QS World University Rankings
IMT Ghaziabad PGDM Admissions...
Apply
AACSB, NBA & SAQS Accredited | H-CTC 41.55 LPA | Merit Based Scholarship
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books