PLEASE EXPLAIN THE NORMALISATION PROCEDURE ADOPTED BY NTA...

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PLEASE EXPLAIN THE NORMALISATION PROCEDURE ADOPTED BY NTA...

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Nischal Jain 29th Mar, 2019

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Unnam sreekanth 29th Mar, 2019

Hello aspirant
.
Mainly normalization is used to know your percentile rank.
Use this formula to predict the rank:

Rank Formula = (100 - your total score) X 145386 /100.
Your rank may differ from the official cutoff and results which were released on the month of April by national testing agency NTA officially.

You have to wait for the official results.
.
If you want more information once visit this below link about normalization :-
.
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-normalisation-process-how-scores-are-calculated/amp
.
If you have any questions please let me know!
.
Thank you!

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Comments (5)

Nischal Jain

29th Mar, 2019

SIR ACCORDING TO A PRESS RELEASE BY NTA, THE NO. OF STUDENTS WHO GAV MAINS ATTEMPT WERE AROUND 8 LAKH 74K, THEN WHY ARE U USING 145386 FOR RANK CALCULATION?

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Unnam sreekanth

29th Mar, 2019

The number I mentioned is for jee mains Paper 2 exam.the number of applicants applied for paper 1 exam is 874469.

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Yahya Nayeem

29th Mar, 2019

But sir total no of candidates are 9.54 lacs
Then how can we use 14 lacs
Please clarify

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Yahya Nayeem

29th Mar, 2019

Please don't create hawock in people's mind
Everybody knows that 9.54 lacs are appearing so how come you are counting for 14.5 lacs
Its not a joke sir
Its career related thing

Reply

Unnam sreekanth

30th Mar, 2019

For April exam there may be increased in number from 8 to 14 lash. Because this year exam held twice.

Reply

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