144 Views

Question of physics of Law of motion


arvy 20th Dec, 2018
Answer (1)
Vikas gehlot 20th Dec, 2018

Since the bomb was initially at rest and it explodes into internal force therefore the total net external force on the bomb is zero and hence linear momentum is conserved.

Therefore let p be the momentum

Then

M+xi-2xj=0

Therefore

M= 2xj-xi

Therefore magnitude of m is X sq root of 5.



1 Comment
Comments (1)
20th Dec, 2018
your answer is right sir thank you
Reply

Related Questions

Amity University | LLM Admiss...
Apply
Ranked as India’s #1 Not for profit pvt. University by India Today.
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Sharda University Admissions ...
Apply
North India's Largest Educational Group | NIRF Ranked 86 | NAAC A+ Grade | Highest Package 1.6 Cr | Applications Closing on 31st July
UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS Rankings | 16.6 LPA Highest CTC | Last Date to...
Sanskaram University LLM Admi...
Apply
100+ Industry collaborations | 10+ Years of legacy
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books