Question : Simplify: $\frac{\cos A}{1+\tan A}-\frac{\sin A}{1+\cot A}$
Option 1: $\tan A$
Option 2: $\cos A-\sin A$
Option 3: $\cos A \sin A$
Option 4: $\cos A+\sin A$
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Correct Answer: $\cos A-\sin A$
Solution : $\frac{\cos A}{1+\tan A}-\frac{\sin A}{1+\cot A}$ $=\frac{\cos A}{1+\frac{\sin A}{\cos A}} - \frac{\sin A}{1+\frac{\cos A}{\sin A}}$ $=\frac{\cos^2 A}{\cos A + \sin A} - \frac{\sin^2 A}{\sin A + \cos A}$ $=\frac{\cos^2 A - \sin^2 A}{\sin A + \cos A}$ $=\frac{(\cos A + \sin A)(\cos A - \sin A)}{\sin A + \cos A}$ $=\cos A - \sin A$ Hence, the correct answer is $\cos A - \sin A$.
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Question : $\frac{\cos A}{1-\tan A}+\frac{\sin A}{1-\cot A}=$___________.
Option 1: $\tan A - \cot A$
Option 2: $\tan A + \cot A$
Option 3: $\sin A - \cos A$
Option 4: $\sin A + \cos A$
Question : Simplify the following. $\frac{\sin^3 \alpha+\cos^3 \alpha}{\sin \alpha+\cos \alpha}$
Option 1: $1+\sin \alpha \cos \alpha$
Option 2: $\tan \alpha$
Option 3: $1-\sin \alpha \cos \alpha$
Option 4: $\sec \alpha$
Question : Simplify the following expression. $\frac{\sin \theta - 2 \sin ^3 \theta}{2 \cos ^3 \theta - \cos \theta}$
Option 1: $\tan \theta$
Option 2: $\sin \theta$
Option 3: $\sec \theta$
Option 4: $\cos \theta$
Question : If A is an acute angle, the simplified form of $\frac{\cos (\pi-A) \cdot \cot \left(\frac{\pi}{2}+A\right) \cos (-A)}{\tan (\pi+A) \tan \left(\frac{3 \pi}{2}+A\right) \sin (2 \pi-A)}$ is:
Option 1: $ \cos^2 A$
Option 2: $\sin A$
Option 3: $\sin^2 A$
Option 4: $\cos A$
Question : Which of the following is equal to $[\frac{\tan \theta+\sec \theta–1}{\tan \theta–\sec \theta+1}]$?
Option 1: $\frac{1+\sin \theta}{\cos \theta}$
Option 2: $\frac{1+\tan \theta}{\cot \theta}$
Option 3: $\frac{1+\cot \theta}{\tan \theta}$
Option 4: $\frac{1+\cos \theta}{\sin \theta}$
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