Question : Simplify the following: $\frac{\cos x-\sqrt{3} \sin x}{2}$
Option 1: $\cos \left(\frac{\pi}{3}-x\right)$
Option 2: $\sin \left(\frac{\pi}{3}+x\right)$
Option 3: $\cos \left(\frac{\pi}{3}+x\right)$
Option 4: $\sin \left(\frac{\pi}{3}-x\right)$
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Correct Answer: $\cos \left(\frac{\pi}{3}+x\right)$
Solution : Given, $\frac{\cos x-\sqrt{3} \sin x}{2}$ = $\frac{1}{2} \cos x-\frac{\sqrt3}{2}\sin x$ = $\cos x \cos \frac{\pi}{3} - \sin \frac{\pi}{3} \sin x$ [$\because\cos \frac{\pi}{3}=\frac{1}{2}$ and $\sin \frac{\pi}{3}=\frac{\sqrt3}{2}$] = $\cos( \frac{\pi}{3}+x)$ Hence, the correct answer is $\cos( \frac{\pi}{3}+x)$.
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Question : In $\triangle{XYZ}$, right-angled at $Y$, if $\sin X = \frac{1}{2}$, find the value of $\cos X \cos Z + \sin X \sin Z$.
Option 1: $\frac{\sqrt{3}}{2}$
Option 2: $\frac{\sqrt{3}}{4}$
Option 3: $\frac{2}{\sqrt{3}}$
Option 4: $\sqrt{3}$
Question : If A is an acute angle, the simplified form of $\frac{\cos (\pi-A) \cdot \cot \left(\frac{\pi}{2}+A\right) \cos (-A)}{\tan (\pi+A) \tan \left(\frac{3 \pi}{2}+A\right) \sin (2 \pi-A)}$ is:
Option 1: $ \cos^2 A$
Option 2: $\sin A$
Option 3: $\sin^2 A$
Option 4: $\cos A$
Question : If $\cos x+\sin x=\sqrt{2} \cos x$, what is the value of $(\cos x-\sin x)^2+(\cos x+\sin x)^2$?
Option 1: $2$
Option 2: $1$
Option 3: $0$
Option 4: $\frac{1}{\sqrt{2}}$
Question : If $\tan \frac{A}{2}=x$, then find $x$.
Option 1: $\frac{\sqrt{1+\cos A}}{\sqrt{1-\cos A}}$
Option 2: $\frac{\sqrt{1-\sin A}}{\sqrt{1+\cos A}}$
Option 3: $\frac{\sqrt{1-\cos A}}{\sqrt{1+\cos A}}$
Option 4: $\frac{\sqrt{\cos A-1}}{\sqrt{1+\cos A}}$
Question : If $\sec x- \cos x$ = 4, then what will be the value of $\frac{\left(1+\cos ^2x\right)}{\cos x}?$
Option 1: $\frac{9}{4}$
Option 2: $\frac{1}{4}$
Option 3: $2\sqrt{5}$
Option 4: $\sqrt{5}$
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