Question : Simplify the following expression. $\frac{\sin \theta - 2 \sin ^3 \theta}{2 \cos ^3 \theta - \cos \theta}$
Option 1: $\tan \theta$
Option 2: $\sin \theta$
Option 3: $\sec \theta$
Option 4: $\cos \theta$
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Correct Answer: $\tan \theta$
Solution : Given: $\frac{\sin \theta - 2 \sin ^3 \theta}{2 \cos ^3 \theta - \cos \theta}$ $=\frac{\sin \theta(1 -2 \sin ^2\theta)}{\cos \theta( 2 \cos ^2\theta - 1)}$ $=\frac{\sin \theta(\sin ^2\theta + \cos^2\theta - 2 \sin ^2\theta)}{\cos \theta( 2\cos ^2\theta - \sin ^2\theta - \cos^2\theta)}$ [as $\sin ^2\theta +\cos^2\theta = 1$] $=\frac{\sin\theta(\cos^{2}\theta - \sin^{2}\theta)}{\cos\theta(\cos^{2}\theta - \sin^{2}\theta)}$ $=\tan \theta$ Hence, the correct answer is $\tan \theta$.
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Question : Which of the following is equal to $[\frac{\tan \theta+\sec \theta–1}{\tan \theta–\sec \theta+1}]$?
Option 1: $\frac{1+\sin \theta}{\cos \theta}$
Option 2: $\frac{1+\tan \theta}{\cot \theta}$
Option 3: $\frac{1+\cot \theta}{\tan \theta}$
Option 4: $\frac{1+\cos \theta}{\sin \theta}$
Question : The expression $\frac{(1-\sin \theta+\cos \theta)^2(1-\cos \theta) \sec ^3 \theta\; {\operatorname{cosec}}^2 \theta}{(\sec \theta-\tan \theta)(\tan \theta+\cot \theta)}, 0^{\circ}<\theta<90^{\circ}$, is equal to:
Option 1: $\sin \theta$
Option 2: $2 \cos \theta$
Option 3: $\cot \theta$
Option 4: $2 \tan \theta$
Question : $\frac{1+\sin \theta}{\cos \theta}$ is equal to which of the following (where $\left.\theta \neq \frac{\pi}{2}\right)?$
Option 1: $\frac{1+\cos \theta}{\sin \theta}$
Option 2: $\frac{\tan \theta+1}{\tan \theta-1}$
Option 3: $\frac{\tan \theta-1}{\tan \theta+1}$
Option 4: $\frac{\cos \theta}{1-\sin \theta}$
Question : What is $\tan \frac{\theta}{2}$?
Option 1: $\frac{\cos \theta}{1-\sin \theta}$
Option 2: $\frac{\sin \theta}{1-\cos \theta}$
Option 3: $\frac{\cos \theta}{1-\cos \theta}$
Option 4: $\frac{\sin \theta}{1+\cos \theta}$
Question : Which of the following is equal to $[\frac{\cos \theta}{\sin \theta}+\frac{\sin \theta}{\cos \theta}]$?
Option 1: $\operatorname{cosec} \theta \sec \theta$
Option 2: $\sec \theta\tan \theta$
Option 3: $\operatorname{cosec} \theta\tan \theta$
Option 4: $\cot \theta \sec \theta$
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