Question : Simplify the given expression $\frac{3\left(\sin ^4 z-\cos ^4 z+1\right)}{\sin ^2 z}$
Option 1: 9
Option 2: 2
Option 3: 4
Option 4: 6
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Correct Answer: 6
Solution : Given, $\frac{3\left(\sin ^4 z-\cos ^4 z+1\right)}{\sin ^2 z}$ Using $a^2-b^2=(a-b)(a+b)$ = $\frac{3((\sin^2z-\cos^2z)(\sin^2z+\cos^2z)+1)}{\sin^2z}$ We know, $\sin^2\theta + \cos^2\theta = 1$ = $\frac{3((\sin^2z-\cos^2z)(1)+1)}{\sin^2z}$ = $\frac{3(\sin^2z+(1-\cos^2z))}{\sin^2z}$ = $\frac{3(\sin^2z+\sin^2z)}{\sin^2z}$ = $\frac{3(2\sin^2z)}{\sin^2z}$ = 6 Hence, the correct answer is 6.
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Question : Simplify the given equation: $(1+\tan ^2 A)(1+\cot ^2 A)=?$
Option 1: $\frac{1}{\cos ^2 A\left(1+\sin ^2 A\right)}$
Option 2: $\frac{1}{\sin ^2 A\left(1-\sin ^2 A\right)}$
Option 3: $\frac{1}{\sin ^2 A+\operatorname{cosec}^2 A}$
Option 4: $\frac{1}{\sin ^2 A\left(1+\cos ^2 A\right)}$
Question : What is the value of $\frac{\sin \theta+\cos \theta}{\sin \theta-\cos \theta}+\frac{\sin \theta-\cos \theta}{\sin \theta+\cos \theta}$?
Option 1: $\frac{1}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 2: $2\left(\sin ^2 \theta-\cos ^2 \theta\right)$
Option 3: $\frac{2}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 4: $\sin ^2 \theta-\cos ^2 \theta$
Question : If $\sin \theta \cos \theta=\frac{\sqrt{2}}{3}$,then the value of $\left(\sin ^6 \theta+\cos ^6 \theta\right)$ is:
Option 1: $\frac{1}{3}$
Option 2: $\frac{4}{3}$
Option 3: $\frac{2}{3}$
Option 4: $\frac{5}{3}$
Question : The value of expression $4\left(\sin ^6 A+\cos ^6 A\right)-6\left(\sin ^4 A+\cos ^4 A\right)+8$ is:
Option 1: 4
Option 2: 8
Option 3: 7
Question : If $\sin A+\sin ^2 A=1$, then the value of the expression $\left(\cos ^2 A+\cos ^4 A\right)$ is
Option 1: $\frac{3}{2}$
Option 2: $1$
Option 3: $2$
Option 4: $\frac{1}{2}$
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