Question : Simplify the given expression. $\sqrt{\frac{1+\cos P}{1-\cos P}}$
Option 1: $\operatorname{cosec}P-\cot P$
Option 2: $\sec P-\tan P$
Option 3: $\sec P+\tan P$
Option 4: $\operatorname{cosec} P+\cot P$
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Correct Answer: $\operatorname{cosec} P+\cot P$
Solution : Given: $\sqrt{\frac{1+\cos P}{1-\cos P}}$ Multiply the numerator and denominator by $1+\cos P$ $=\sqrt{\frac{(1+\cos P)^2}{(1-\cos P)(1+\cos P)}}$ $=\sqrt{\frac{(1+\cos P)^2}{(1-\cos^2 P)}}$ $=\sqrt{\frac{(1+\cos P)^2}{(\sin^2 P)}}$ $=\frac{(1+\cos P)}{(\sin P)}$ $=\operatorname{cosec}P + \cot P$ Hence, the correct answer is $\operatorname{cosec}P + \cot P$.
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Question : What is the value of $\sqrt{\frac{\operatorname{cosec} A+1}{\operatorname{cosec} A-1}}+\sqrt{\frac{\operatorname{cosec} A-1}{\operatorname{cosec} A+1}}$?
Option 1: $2 \cos A$
Option 2: $\sec A$
Option 3: $2\cos A$
Option 4: $2 \sec A$
Question : The given expression is equal to: $1-\frac{\tan ^2 \phi}{\sec ^2 \phi}$
Option 1: $\operatorname{sin}^2 \phi\cos ^2 \phi$
Option 2: $\operatorname{sin}^2 \phi\cot ^2 \phi$
Option 3: $\cot^2 \phi \cos^2 \phi$
Option 4: $\tan^2 \phi\cos^2 \phi$
Question : What is the value of $\frac{\cot \theta+\operatorname{cosec} \theta-1}{\cot \theta-\operatorname{cosec} \theta+1}$?
Option 1: $2 \sec \theta$
Option 2: $2 \operatorname{cosec} \theta$
Option 3: $2 \cot \theta$
Option 4: $\operatorname{cosec} \theta+\cot \theta$
Question : Simplify the given equation: $\frac{\cot^3A–1}{\cot A–1}$
Option 1: $\operatorname{cosec}^2 \mathrm{A}-\cot \mathrm{A}$
Option 2: $\operatorname{cosec}^2 A+\cot A$
Option 3: $\cot ^2 \mathrm{A}+\operatorname{cosec} \mathrm{A}$
Option 4: $\cot ^2 \mathrm{A}-\operatorname{cosec} \mathrm{A}$
Question : The given expression is equal to: $\frac{\left(1+\tan^2 A\right)}{\operatorname{cosec}^2 A \cdot \tan A}$
Option 1: $\sec^2A$
Option 3: $\tan A$
Option 4: $\tan^2A$
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