Hello!

Can you please check the question once again incase if the equation is x^2+6x+7

Then it would be like

x^2+6x-7=0

x^2+7x-x-7=0

x(x+7)-1(x+7)=0

(x+7)(x-1)=0

x = -7, 1

Incase the equation is right then check whether this method is a solution x^2+6x+7

x(x+6)+7 = 0              (taking x to the other side) (anything divided by 0 is 0)

(x+6)+7 = 0

x+6+7 = 0

x+13 = 0

x= -13

ALL THE BEST. Hope the answer was of some help.

Thank You

Dear,

Using Quadratic Formula-

x ² + 6x + 7 = 0

x ₁ = −6 − √ 62 − 4×1×7 / 2×1

= −6 − 2 × √ 2 /  2

≈  −4.414

x ₂ = −6 + √ 62 − 4×1×7 / 2×1

= −6 + 2 × √ 2 / 2

≈ −1.586

Extrema:-   Min(-3,-2)