Given, x-3y=4 ⇒ x=4+3y
Now substituting x=4+3y in 2x+y=1
2(4+3y)+y=1
8+6y+y=1
7y=1-8 ⇒ y=-1
Substitute y=-1 in x-3y=4
x-3(-1)=4
x=4-3 ⇒ x=1
Thus (x, y)=(1, -1)
Question : Simplify the given expression. $(x - 2y)(y - 3x) + (x + y)(x - y) + (x - 3y)(2x + y)$
Option 1: $2y(x - 3y)$
Option 2: $2y(x + 3y)$
Option 3: $2x(x - 3y)$
Option 4: $2x(x + 3y)$
Question : If $( x^{3}-y^{3}):( x^{2}+xy+y^{2})=5:1$ and $( x^{2}-y^{2}):(x-y)=7:1$, then the ratio $2x:3y$ equals:
Option 1: $4:1$
Option 2: $2:3$
Option 3: $4:3$
Option 4: $3:2$
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