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target loses half of its velocity after penetrating 3cm. How much further it will penetrate before coming to rest, assuming that it faces constant resistance to motion? (Provide your answer in cm) [neglect gravity]


Paul Vijay vardhan 9th Apr, 2020
Answer (1)
Sai Sri Nandan Ch 9th Apr, 2020

Hello,

To solve this problem, we'll use the formula

v^2 - u^2 = 2as.

Here v is final velocity.

v is u/2 at distance s=3cm.

We have to find the value of a.

Substituting the values, we get:

a= -1 * (u^2 / 12). ----- Let this be equation 1.

In case 2, using the same formula,

now, initial velocity u is u/2. Final velocity v is 0.

a is substituted from eq. 1.

Hence we get, 0 - (u/2)^2 = 2 * s * (-u^2/12)

Therefore, s = 3cm. This is the distance the target travels before coming to rest.

Hope this helps.

Thanks.

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