Question : The altitude of an equilateral triangle of side $\frac{2}{\sqrt3}$ cm is:
Option 1: $\frac{4}{3}$ cm
Option 2: $\frac{4}{\sqrt3}$ cm
Option 3: $\frac{2}{3}$ cm
Option 4: $1$ cm
Correct Answer: $1$ cm
Solution : Given: Side of equilateral triangle = $\frac{2}{\sqrt3}$ m Altitude of an equilateral triangle of side $a$ = $\frac{\sqrt3}{2}a$ $\therefore$ The altitude of the triangle is $\frac{\sqrt3}{2}×\frac{2}{\sqrt3}$ = 1 cm Hence, the correct answer is $1$ cm.
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Question : If the area of an equilateral triangle is $a$ and height $b$, then the value of $\frac{b^2}{a}$ is:
Option 1: $3$
Option 2: $\frac{1}{3}$
Option 3: $\sqrt3$
Option 4: $\frac{1}{\sqrt3}$
Question : ABCD is a square. Draw an equilateral $\triangle $PBC on side BC considering BC is a base and an equilateral $\triangle $QAC on diagonal AC considering AC is a base. Find the value of $\frac{\text{area of $\triangle PBC$}}{\text{area of $\triangle QAC$}}$.
Option 1: $\frac{1}{2}$
Option 2: $1$
Option 3: $\frac{1}{3}$
Option 4: $\frac{1}{4}$
Question : The area of an equilateral triangle is $4 \sqrt{3} \mathrm{~cm}^2$. Find the side (in cm) of the triangle.
Option 1: $2$
Option 2: $4$
Option 3: $\sqrt{3}$
Option 4: $2 \sqrt{3}$
Question : If each side of an equilateral triangle is 12 cm, then its altitude is equal to:
Option 1: $6 \sqrt{3}\ \text{cm}$
Option 2: $3 \sqrt{6}\ \text{cm}$
Option 3: $6 \sqrt{2}\ \text{cm}$
Option 4: $3 \sqrt{2}\ \text{cm}$
Question : The area of an equilateral triangle is 173.2 cm2. Its side will be __________.
Option 1: 20 cm
Option 2: 22 cm
Option 3: 17.32 cm
Option 4: 21.32 cm
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