Hi Candidate,

The graph is given by a quadratic equation comprising of x.x, x and constants. The graph of y=x.x+4x+5 is bound in x and y co-ordinates which intersects the y-axis at x=0 and y=5 while the graph intresects the x axis at imaginary co-ordinates- x= -2+i, -2-i, Where I stands for iota.

If we take its point of maximus it's at x=-2 or the value of first derivative occurs at x=-2. It is not possible to find the real area of the graph since it has imaginary co-ordinates on x axis.

Have a Good Day.