Question : The average of prime numbers between 1 and 20 is:
Option 1: $9$
Option 2: $9\frac{5}{8}$
Option 3: $10\frac{1}{8}$
Option 4: $8$
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Correct Answer: $9\frac{5}{8}$
Solution : Prime numbers from 1 to 20 are 2, 3, 5, 7, 11, 13, 17 and 19. Average = $\frac{\text{Sum of all observations}}{{\text{Total number of observations}}}=\frac{(2 + 3 + 5 + 7 + 11 + 13 + 17 + 19)}{8}=\frac{77}{8}=9\frac{5}{8}$ Hence, the correct answer is $9\frac{5}{8}$.
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Question : Determine the correct answer for $(\frac{1}{8}+\frac{9}{4}-3)$:
Option 1: $\frac{2}{8}$
Option 2: $\frac{7}{8}$
Option 3: $-\frac{5}{8}$
Option 4: $-\frac{3}{8}$
Question : Of the three numbers, the first is twice the second, and the second is twice the third. The average of the reciprocal of the numbers is $\frac{7}{12}$. The numbers are:
Option 1: 20, 10 and 5
Option 2: 4, 2 and 1
Option 3: 36, 18 and 9
Option 4: 16, 8 and 4
Question : The value of $\frac{3}{8}+\left[\left(\frac{4}{8} \div \frac{2}{3}\right) \times \frac{8}{5}+\frac{3}{10}\right]$ is:
Option 1: $\frac{15}{8}$
Option 2: $\frac{3}{8}$
Option 3: $\frac{3}{2}$
Option 4: $\frac{15}{2}$
Question : The value of $\frac{2}{3} \times \frac{6}{5} \times \frac{10}{4}+\frac{1}{8}-\frac{3}{8}$ is:
Option 1: $\frac{4}{3}$
Option 2: $\frac{3}{4}$
Option 3: $\frac{4}{7}$
Option 4: $\frac{7}{4}$
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