Hey!There
This problem is Soo simple.To get equation of desired circle you need to find the centre of two citcle..For that go through the general equation of circle and compare with this...On comparing with standard equation you will get centre of two circle..And from these two centre you can easily get equation of desired circle.i.e (x-x1)(x-x2)+(y-y1)(y-y2)..Or you can find mid point of these two points which will be centre of desired circle and radius will be half of distance between these two points. You have two ways to reach at solution choices yours..
Ask if any query
Question : The graphs of the equations $4 x+\frac{1}{3} y=\frac{8}{3}$ and $\frac{1}{2} x+\frac{3}{4} y+\frac{5}{2}=0$ intersect at a point P. The point P also lies on the graph of the equation:
Option 1: $x + 2y - 5 = 0$
Option 2: $3x - y - 7 = 0$
Option 3: $x - 3y - 12= 0$
Option 4: $4x - y + 7= 0$
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