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the edge length of fcc unit cell is 400pm.if molar mass is 60.22g/mol.then find the density for na=6.022×1023


kavitha24 27th Jul, 2020
Answer (1)
Disha Arora 27th Jul, 2020

Hi

According to the question For an FCC crystal, atoms are in touch along the diagonal of the unit .

4r= 2

a, where a is that the edge length of unit and r is that the radius of atom.

Substituting values within the above expression, we get

r= 42 ×407

=143.9 pm

Number of atoms per unit cell (FCC) =4

Mass of 1 unit cell =197×4=788amu=1.66×10 −27 ×788kg=1.30808×10 −24 kg

Volume of 1 unit cell =(407×10 −12 ) 3 m 3 =6.741×10 −29 m 3 =2.824×10 −28 m 3

Density= 6.741×10 −29

1.30808×10 −24

=19404.83kg/m 3 =19.4g/cm 3

Hope helpful.

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