426 Views

the edge length of fcc unit cell is 400pm.if molar mass is 60.22g/mol.then find the density for na=6.022×1023


kavitha24 27th Jul, 2020
Answer (1)
Disha Arora 27th Jul, 2020

Hi

According to the question For an FCC crystal, atoms are in touch along the diagonal of the unit .

4r= 2

a, where a is that the edge length of unit and r is that the radius of atom.

Substituting values within the above expression, we get

r= 42 ×407

=143.9 pm

Number of atoms per unit cell (FCC) =4

Mass of 1 unit cell =197×4=788amu=1.66×10 −27 ×788kg=1.30808×10 −24 kg

Volume of 1 unit cell =(407×10 −12 ) 3 m 3 =6.741×10 −29 m 3 =2.824×10 −28 m 3

Density= 6.741×10 −29

1.30808×10 −24

=19404.83kg/m 3 =19.4g/cm 3

Hope helpful.

Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Indus University M.Tech Admis...
Apply
Highest CTC 26 LPA | Top Recruiters: Accenture, TCS, Tech Mahindra, Capgemini, Microsoft
Greater Noida Institute of Te...
Apply
NAAC A+ Accredited | Highest CTC 70 LPA | Average CTC 6.5 LPA | 400+ Recruiters
Vignan's Deemed to be Univers...
Apply
70th University Ranked by NIRF | 80th Engineering Rank by NIRF | Accredited by NBA and NAAC A+
Amity University-Noida BBA Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
UPES B.Tech Admissions 2026
Apply
Last Date to Apply: 26th March | Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books