Greetings, Aspirant
The energies of an electron in the first and sixth energy level can be compared as
E 1 /E 2 = (n 2 /n 1 ) 2
=> 42 eV/ E 2 = (6 / 1) 2 => 42 eV / E 2 = 36
=> E 2 = (42/36) eV = 1.16 eV
The answer does not match any of the given options. I hope it helps.
Thank you
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