Question : The LCM of two prime numbers x and y (x > y) is 533. The value of 4y – x is:
Option 1: 18
Option 2: 11
Option 3: 23
Option 4: 21
Correct Answer: 11
Solution : 533 = 13 × 41 So, x = 41 and y = 13 (Since x and y are prime numbers) Now, (4y − x) = (4 × 13 – 41) = 11 Hence, the correct answer is 11.
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Question : If $x^4+x^2 y^2+y^4=21$ and $x^2+xy+y^2=3$, then what is the value of $4xy $?
Option 1: –8
Option 2: 4
Option 3: –4
Option 4: 12
Question : If $x$ and $y$ are real numbers, then the least possible value of $4 (x -2)^2+ (y-3)^2-2 (x-3)^2$ is:
Option 1: 3
Option 2: –4
Option 3: 1
Option 4: –8
Question : If $x + y + z = 19, x^2 + y^2 + z^2 = 133$ and $xz = y^2, x > z > 0,$ what is the value of $(x - z)$?
Option 1: 5
Option 2: 0
Option 3: –2
Option 4: –5
Question : If $x+y+z=17, x y z=171$ and $x y+y z+z x=111$, then the value of $\sqrt[3]{\left(x^3+y^3+z^3+x y z\right)}$ is:
Option 1: –64
Option 3: 0
Option 4: –4
Question : If $x^2 = y+z$, $y^2=z+x$, $z^2=x+y$, then the value of $\frac{1}{x+1}+\frac{1}{y+1}+\frac{1}{z+1}$ is:
Option 1: –1
Option 2: 1
Option 3: 2
Option 4: 4
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