Question : The L.C.M. of two prime numbers x and y (x>y) is 161. The value of (3y - x):
Option 1: -2
Option 2: -1
Option 3: 1
Option 4: 2
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Correct Answer: -2
Solution : 161 has the only prime factor is (7, 23) and (x>y) so x = 23, y = 7 The value of (3y - x) = 3×7-23 = 21-23 = -2
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Question : If $x^2+y^2=29$ and $xy=10$, where $x>0,y>0$ and $x>y$. Then the value of $\frac{x+y}{x-y}$ is:
Option 1: $- \frac{7}{3}$
Option 2: $\frac{7}{3}$
Option 3: $\frac{3}{7}$
Option 4: $-\frac{3}{7}$
Question : If $x=(0.25)^\frac{1}{2}$, $y=(0.4)^{2}$, and $z=(0.216)^{\frac{1}{3}}$, then:
Option 1: $y>x>z$
Option 2: $x>y>z$
Option 3: $z>x>y$
Option 4: $x>z>y$
Question : The third proportional of the following numbers $(x-y)^2, (x^2-y^2)^2$ is:
Option 1: $(x+y)^3(x-y)^2$
Option 2: $(x+y)^4(x-y)^2$
Option 3: $(x+y)^2(x-y)^2$
Option 4: $(x+y)^2(x-y)^3$
Question : If $xy(x+y)=m$, then the value of $(x^3+y^3+3m)$ is:
Option 1: $\frac{m^3}{xy}$
Option 2: $\frac{m^3}{(x+y)^3}$
Option 3: $\frac{m^3}{x^3y^3}$
Option 4: $mx^3y^3$
Question : What is the value of $64 x^3+38 x^2 y+20 x y^2+y^3$, when $x=3$ and $y=-4$?
Option 1: 1236
Option 2: 488
Option 3: 536
Option 4: 1256
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