Question : The least value of $\tan^2x+\cot^2x$ is:
Option 1: 3
Option 2: 2
Option 3: 0
Option 4: 1
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Correct Answer: 2
Solution : The value will be minimum when $x = 45°$ Minimum value $= \tan^2x+\cot^2x=\tan^245°+\cot^245°=1+1=2$ Hence, the correct answer is 2.
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Question : What will be the value of $\cos x \operatorname{cosec} x - \sin x \sec x$?
Option 1: $\cot \frac{2x}{2}$
Option 2: $\tan 2 x $
Option 3: $\cot 2 x $
Option 4: $ 2 \cot 2x$
Question : If $\cos^2x+\cos^4x=1$, then $\tan^2x+\tan^4x$?
Option 1: $0$
Option 2: $1$
Option 3: $2 \tan^2x$
Option 4: $2\tan^4x$
Question : The value of tan 25° tan 35° tan 45° tan 55° tan 65° is:
Option 1: $2$
Option 3: $\sqrt{3}$
Option 4: $0$
Question : If $\tan\theta-\cot\theta=0$ and $\theta$ is positive acute angle, then the value of $\frac{\tan(\theta+15)}{\tan(\theta-15)}$ is:
Option 1: $3$
Option 2: $\frac{1}{\sqrt{3}}$
Option 3: $\frac{1}{3}$
Option 4: $\sqrt{3}$
Question : If $\theta$ is an acute angle and $\tan \theta+\cot \theta=2$, then the value of $\tan ^{200} \theta+\cot ^{200} \theta$ is:
Option 1: 1
Option 3: –1
Option 4: 0
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