Question : The length of a cuboid is 4 cm. If the breadth of the cuboid is four times its length and the height of the cuboid is twice its length, then what is the lateral surface area of the cuboid?
Option 1: 380 cm2
Option 2: 440 cm2
Option 3: 260 cm2
Option 4: 320 cm2
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Correct Answer: 320 cm2
Solution : Given that: Length, L = 4 cm Breadth, B = four times the length (L), so B = 4L Height, H = two times the length (L), so H = 2L Now, substitute the given values: ⇒ L = 4 cm, B = 4 × 4 =16 cm, and H = 2 × 4 = 8 cm Lateral surface area (LSA) = 2 × H × (L + B) = 2 × 8 × (4 + 16) = 2 × (32 + 128) = 2 × 160 = 320 cm2 Hence, the correct answer is 320 cm2.
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Question : The length of a cuboid is six times its breadth and the height of a cuboid is four times its breadth. If the breadth of the cuboid is 3 cm, then what is the total surface area of the cuboid?
Option 1: 484 cm2
Option 2: 612 cm2
Option 3: 576 cm2
Option 4: 676 cm2
Question : The length of a cuboid is 10 cm. If the breadth of the cuboid is half of its length and the height of the cuboid is twice its length, then what is the lateral surface area of the cuboid?
Option 1: 600 cm2
Option 2: 500 cm2
Option 3: 720 cm2
Option 4: 560 cm2
Question : The length of a cuboid is half of its breadth and the height of the cuboid is thrice of its breadth. If the breadth of the cuboid is 12 cm, then what is the total surface area of the cuboid?
Option 1: 1680 cm2
Option 2: 1320 cm2
Option 3: 1440 cm2
Option 4: 1560 cm2
Question : The sum of the length and breadth of a cuboid is 16 cm. If the height of the cuboid is one-fourth of the sum of its length and breadth, then what is the lateral surface area of the cuboid?
Option 1: 128 cm2
Option 2: 196 cm2
Option 3: 96 cm2
Option 4: 156 cm2
Question : The sum of the length and breadth of a cuboid is 40 cm. If the height of the cuboid is $\frac{1}{5}$ of the sum of its length and breadth, then what is the lateral surface area of the cuboid?
Option 1: $580 {~cm}^2$
Option 2: $320 {~cm}^2$
Option 3: $640 {~cm}^2$
Option 4: $720 {~cm}^2$
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