Question : The length of the base of a triangle is 10 cm and its altitude from the same base is 8 cm. What is the area of the triangle?
Option 1: 30 cm2
Option 2: 40 cm2
Option 3: 50 cm2
Option 4: 80 cm2
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Correct Answer: 40 cm2
Solution : Base = 10 cm Altitude = 8 cm Area = $\frac{1}{2} \times \text {base} \times \text {altitude}$ Substituting these values into the formula, we get: Area = $\frac{1}{2} × 10 × 8$ Area = $5 × 8$ Area = 40 cm2 Hence, the correct answer is 40 cm2.
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Question : If the altitude of a triangle is 8 cm and its corresponding base is 12 cm, then the area of the triangle will be:
Option 1: 96 cm2
Option 2: 48 cm2
Option 3: 84 cm2
Option 4: 24 cm2
Question : The altitude drawn to the base of an isosceles triangle is 8 cm and its perimeter is 64 cm. The area (in cm2) of the triangle is:
Option 1: 240
Option 2: 180
Option 3: 360
Option 4: 120
Question : The sides of a triangle are of length 8 cm, 15 cm, and 17 cm. Find the area of the triangle.
Option 1: 65 cm2
Option 2: 75 cm2
Option 3: 60 cm2
Option 4: 70 cm2
Question : If the altitude of a right prism is 10 cm and its base is an equilateral triangle of side 12 cm, then its total surface area (in cm2) is:
Option 1: $(5+3\sqrt3)$
Option 2: $36\sqrt3$
Option 3: $360$
Option 4: $72(5+\sqrt3)$
Question : Find the area of a right-angled triangle whose base is 12 cm and the hypotenuse is 13 cm.
Option 2: 55 cm2
Option 3: 65 cm2
Option 4: 22 cm2
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