Question : The mean of 9 observations is 16. When one more observation is included, the new mean becomes 17. What is the value of the 10th observation?
Option 1: 9
Option 2: 16
Option 3: 26
Option 4: 30
Correct Answer: 26
Solution : Given: The mean of 9 observations is 16. One more observation is included and the new mean after becomes 17. Tenth observation = sum of ten observations – sum of nine observations = (17 × 10) – (16 × 9) = 170 – 144 = 26 Hence, the correct answer is 26.
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Question : The average of $n$ observations is 40. If one observation of value 80 is added, then the average of all the observations is 41. What is the value of $n$?
Option 1: 40
Option 2: 39
Option 3: 38
Option 4: 43
Question : If $\cos\theta=\frac{3}{5}$, then the value of $\sin\theta.\sec\theta.\tan\theta$ is:
Option 1: $\frac{9}{16}$
Option 2: $\frac{16}{9}$
Option 3: $\frac{3}{4}$
Option 4: $\frac{4}{3}$
Question : What is the least value of x so that the number 8x5215 becomes divisible by 9?
Option 1: 3
Option 2: 1
Option 3: 5
Option 4: 6
Question : The value of $\frac{2}{3} \div \frac{3}{10}$ of $\frac{4}{9}-\frac{4}{5} \times 1 \frac{1}{9} \div \frac{8}{15}+\frac{3}{4} \div \frac{1}{2}$ is:
Option 1: $\frac{29}{6}$
Option 2: $\frac{17}{9}$
Option 3: $\frac{14}{3}$
Option 4: $\frac{49}{12}$
Question : The value of $\frac{2}{3} \div \frac{3}{10}$ of $\frac{4}{9}-\frac{4}{5} \times 1 \frac{1}{9} \div \frac{8}{15}-\frac{3}{4}+\frac{3}{4} \div \frac{1}{2}$ is:
Option 1: $\frac{25}{6}$
Option 2: $\frac{14}{3}$
Option 3: $\frac{17}{9}$
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