Question : The next number of the sequence $\frac{1}{2},\frac{3}{4},\frac{5}{8},\frac{7}{16},........$ is:
Option 1: $\frac{10}{24}$
Option 2: $\frac{11}{32}$
Option 3: $\frac{9}{24}$
Option 4: $\frac{9}{32}$
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Correct Answer: $\frac{9}{32}$
Solution : The given sequence seems to follow a pattern. The numerator of each fraction increases by 2 and the denominator is a power of 2. For the next term, following the pattern, the numerator should be 7 + 2 = 9. The denominator, being powers of 2, should be the next power of 2 after 16, which is 32. So, the next number in the sequence should be $\frac{9}{32}$. Hence, the correct answer is $\frac{9}{32}$.
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Question : The arrangement of the fractions $\frac{4}{3}, -\frac{2}{9}, -\frac{7}{8}, \frac{5}{12}$ in ascending order is _____.
Option 1: $–\frac{7}{8}, –\frac{2}{9}, \frac{5}{12}, \frac{4}{3}$
Option 2: $–\frac{7}{8}, –\frac{2}{9}, \frac{4}{3}, \frac{5}{12}$
Option 3: $–\frac{2}{9}, –\frac{7}{8}, \frac{5}{12}, \frac{4}{3}$
Option 4: $–\frac{2}{9}, –\frac{7}{8}, \frac{4}{3}, \frac{5}{12}$
Question : If $\left(4y-\frac{4}{y}\right)=11$, find the value of $\left(y^2+\frac{1}{y^2}\right)$.
Option 1: $7 \frac{9}{16}$
Option 2: $5 \frac{9}{16}$
Option 3: $9 \frac{11}{16}$
Option 4: $9 \frac{9}{16}$
Question : Find the sum of the first five terms of the following series: $\frac{1}{1×4} + \frac{1}{4×7}+\frac{1}{7×10}+...$
Option 1: $\frac{9}{32}$
Option 2: $\frac{7}{16}$
Option 3: $\frac{5}{16}$
Option 4: $\frac{1}{210}$
Question : Find the value of the given expression: $\frac{(4\frac{1}{3}+3\frac{1}{3}\times 1\frac{4}{5}\div 3\frac{3}{4}\times (1\frac{1}{2}+1\frac{1}{3}))}{(\frac{2}{3}\div \frac{5}{6}\times \frac{2}{3})}$
Option 1: $11 \frac{3}{8}$
Option 2: $10\frac{1}{8}$
Option 3: $14\frac{3}{8}$
Option 4: $16\frac{5}{8}$
Question : If $\sqrt{\frac{\mathrm{a}}{\mathrm{b}}}=\frac{8}{3}-\sqrt{\frac{\mathrm{b}}{\mathrm{a}}}$ and $a-b=10$, then the value of $ab$ is:
Option 1: $32 \frac{1}{7}$
Option 2: $32 \frac{3}{7}$
Option 3: $32 \frac{4}{7}$
Option 4: $32 \frac{2}{7}$
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