374 Views

the oxidation State of ruthenium in compound K2Ru(OH)Cl5


Yogesh Kumar bharti 21st Jul, 2020
Answer (1)
Kamal Kishor Chaurasiya 21st Jul, 2020

Hi aspirant,


The oxidation state is a number assigned to an element in chemical combination which represents the number of electrons lost (or gained, if the number is negative), by an atom of that element in the compound.

In case of your compound the elements are:

  • K with +1 oxidation state
  • Cl with -1 oxidation state
  • OH with -1 oxidation state

Now we can calculate the oxidation state of Ru as:

2*1+(OS of Ru)+1*(-1)+(-1)*5=0

=> (OS of Ru) -4=0

=> OS of Ru =4


Hope this helps.

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Amity University Noida MBA Ad...
Apply
Amongst top 3% universities globally (QS Rankings) | Ranked among top 10 B-Schools in India by multiple publications
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
MAHE Online MBA
Apply
Apply for Online MBA from Manipal Academy of Higher Education (MAHE)
FLAME University | MBA 2026
Apply
NAAC A++ Grade | MBA program graded A** (National) by CRISIL | AACSB, ACBSP and BGA Member
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books