Question : The perimeter of a certain isosceles right triangle is $10+10\sqrt{2}$ cm. What is the length of the Hypotenuse of the triangle?
Option 1: $5$ cm
Option 2: $10$ cm
Option 3: $5\sqrt{2}$ cm
Option 4: $10\sqrt{2}$ cm
Correct Answer: $10$ cm
Solution : \(\text{Perimeter} = \text{Sum of all sides}\) Sides of an isosceles right triangle are $a, a, and $\sqrt{2}a$$ So, \(\text{Perimeter} = a+a+\sqrt{2}a \) \(=10+10\sqrt{2} \) ⇒ \((2a+\sqrt{2}a)=(10+10\sqrt{2}) \) ⇒ \(\sqrt{2}a(1+\sqrt{2})=10(1+\sqrt{2}) \) ⇒ \(a=\frac{10}{\sqrt{2}} \) ⇒ BC (Hypotenuse) = \(\sqrt{2}a\) ⇒ \(\frac{\sqrt{2} \times 10}{\sqrt{2}}=10\ \mathrm{cm} \) Hence, the correct answer is $10$ cm.
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Question : If the hypotenuse of an isosceles right-angled triangle is 10 cm, then the other two sides (in cm) are __________.
Option 1: $10\sqrt{2}$ and $10\sqrt{2}$
Option 2: $8\sqrt{2}$ and $8\sqrt{2}$
Option 3: $6\sqrt{2}$ and $6\sqrt{2}$
Option 4: $5\sqrt{2}$ and $5\sqrt{2}$
Question : The perimeter of a right triangle is 60 cm and its hypotenuse is 26 cm. What is the area (in cm2) of the triangle?
Option 1: 60
Option 2: 96
Option 3: 90
Option 4: 120
Question : Find the area of a triangle whose length of two sides are 4 cm and 5 cm and the angle between them is 45°.
Option 1: $4 \sqrt{2} \mathrm{~cm}^2$
Option 2: $7 \sqrt{2} \mathrm{~cm}^2$
Option 3: $5 \sqrt{2} \mathrm{~cm}^2$
Option 4: $6 \sqrt{2} \mathrm{~cm}^2$
Question : What is the area of a triangle having a perimeter of 32 cm, one side of 11 cm, and the difference between the other two sides is 5 cm?
Option 1: $8\sqrt{30}$ cm2
Option 2: $5\sqrt{35}$ cm2
Option 3: $6\sqrt{30}$ cm2
Option 4: $8\sqrt{2}$ cm2
Question : In triangle ABC which is equilateral. O is the point of intersection of altitude AL, BM, and CN. If OA = 16 cm, what is the semi-perimeter of the triangle ABC?
Option 1: $8 \sqrt 3$ cm
Option 2: $12 \sqrt 3$ cm
Option 3: $16 \sqrt 3$ cm
Option 4: $24\sqrt 3$ cm
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