Question : The ratio of the area of a regular hexagon and an equilateral triangle having the same perimeter is:
Option 1: $2:3$
Option 2: $6:1$
Option 3: $3:2$
Option 4: $1:6$
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Correct Answer: $3:2$
Solution : Given: A regular hexagon and an equilateral triangle having the same perimeter. Let the perimeter of the triangle and the hexagon be $6a$ units. So, each side of the hexagon = $a$ units And each side of the triangle = $2a$ units We know that the area of a regular hexagon = $\frac{3\sqrt3}{2}a^2$ and the area of an equilateral triangle = $\frac{\sqrt3}{4}b^2$, where $a$ and $b$ are the sides of the hexagon and the equilateral triangle, respectively. So, the area of the hexagon = $\frac{3\sqrt3}{2}a^2$ sq. units And the area of the equilateral triangle = $\frac{\sqrt3}{4}(2a)^2$ sq. units $\therefore$ The ratio of their area $=\frac{3\sqrt3}{2}a^2 : \frac{\sqrt3}{4}(2a)^2 = \frac{3}{2}:1 = 3:2$ Hence, the correct answer is $3:2$.
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Question : The ratio of the area of an equilateral triangle and that of its circumcircle is:
Option 1: $2\sqrt3:2\pi$
Option 2: $4:\pi$
Option 3: $3\sqrt3:4\pi$
Option 4: $7\sqrt2:2\pi$
Question : A circle is inscribed in an equilateral triangle and a square is inscribed in that circle. The ratio of the areas of the triangle and the square are:
Option 1: $\sqrt3:4$
Option 2: $\sqrt3:8$
Option 3: $3\sqrt3:2$
Option 4: $3\sqrt3:1$
Question : The perimeter of an equilateral triangle is 40 cm more than the length of each of its sides. What is the length of each side of this equilateral triangle?
Option 1: 10 cm
Option 2: 30 cm
Option 3: 15 cm
Option 4: 20 cm
Question : The longest side of the obtuse triangle is 7 cm and the other two sides of the triangle are 4 cm and 5 cm. Find the area of the triangle.
Option 1: $1 \sqrt{3} \mathrm{~cm}^2$
Option 2: $6 \sqrt{3} \mathrm{~cm}^2$
Option 3: $3 \sqrt{2} \mathrm{~cm}^2$
Option 4: $4 \sqrt{6} \mathrm{~cm}^2$
Question : A, B, and C are assigned to complete a work. If the ratio of time taken by A, B, and C is 4 : 3 : 6. Find the ratio of their efficiency.
Option 1: 3 : 4 : 2
Option 2: 4 : 3 : 6
Option 3: 3 : 4 : 6
Option 4: 4 : 6 : 8
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