Question : The side of an equilateral triangle is 36 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $13 \sqrt{3} \mathrm{~cm}$
Option 2: $10 \sqrt{3} \mathrm{~cm}$
Option 3: $12 \sqrt{3} \mathrm{~cm}$
Option 4: $9 \sqrt{3} \mathrm{~cm}$
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Correct Answer: $12 \sqrt{3} \mathrm{~cm}$
Solution : Length of side of given equilateral triangle, $a$ = 36 cm We know that circumradius of an equilateral triangle $=\frac{a}{\sqrt{3}}=\frac{36}{\sqrt{3}}=12\sqrt{3}$ Hence, the correct answer is $12 \sqrt{3} \mathrm{~cm}$.
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Question : The side of an equilateral triangle is 9 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $2\sqrt{3}$ cm
Option 2: $5\sqrt{3}$ cm
Option 3: $4\sqrt{3}$ cm
Option 4: $3\sqrt{3}$ cm
Question : The side of an equilateral triangle is 12 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $6 \sqrt{3}\ \text{cm}$
Option 2: $4\sqrt{3}\ \text{cm}$
Option 3: $9 \sqrt{3}\ \text{cm}$
Option 4: $5\sqrt{3}\ \text{cm}$
Question : The height of an equilateral triangle is $9 \sqrt{3} \mathrm{~cm}$. What is the area of this equilateral triangle?
Option 1: $92 \sqrt{3} \mathrm{~cm}^2$
Option 2: $67 \sqrt{3} \mathrm{~cm}^2$
Option 3: $49 \sqrt{3} \mathrm{~cm}^2$
Option 4: $81 \sqrt{3} \mathrm{~cm}^2$
Question : ABC is an equilateral triangle. If the area of the triangle is $36 \sqrt{3}$, then what is the radius of the circle circumscribing the $\triangle ABC$?
Option 1: $2 \sqrt{3}$
Option 2: $3 \sqrt{3}$
Option 3: $4 \sqrt{3}$
Option 4: $6 \sqrt{3}$
Question : ABC is an equilateral triangle with a side of 12 cm. What is the length of the radius of the circle inscribed in it?
Option 1: $2 \sqrt{3}$ cm
Option 2: $8 \sqrt{3}$ cm
Option 3: $4 \sqrt{3} $ cm
Option 4: $6 \sqrt{3}$ cm
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