Question : The sides of a triangular park are 60 m, 112 m and 164 m. The cost of levelling the park at the rate of INR 8.50/m2 is:
Option 1: INR 18,164
Option 2: INR 17,085
Option 3: INR 17,136
Option 4: INR 18,316
Correct Answer: INR 17,136
Solution : Given: a = 60 m b = 112 m c = 164 m Rate = INR 8.50/m2 Now, Semi perimeter, $(S) = \frac{60\ +\ 112\ +\ 164 }{2} =\ 168$ Area of the triangle $A\ = \sqrt{168(168\ -\ 60)(168\ -\ 112)(168\ -\ 164)} $ $⇒A\ = \sqrt{168\ \times 108\ \times 56\ \times 4}$ $\therefore A\ = 2016$ m2 So, the cost of levelling of 2016 m2 of the park $=\ 8.5\ \times 2016$ $=17136$ Hence, the correct answer is INR 17136.
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Question : The sides of a triangular park are 35 m, 53 m, and 66 m. The cost of levelling the park at the rate of INR 9.25 per m2 is:
Option 1: INR 8,584
Option 2: INR 8,547
Option 3: INR 8,621
Option 4: INR 8,510
Question : The sides of a triangular field are 120 m, 170 m and 250 m. The cost of levelling the field at the rate of INR 7.40/m2 is:
Option 1: INR 65,120
Option 2: INR 63,640
Option 3: INR 59,200
Option 4: INR 66,600
Question : The internal length of a room is two times its breadth and three times its height. The total cost of painting its four walls at the rate of INR 25/m2 is INR 3,600. What is the cost of laying a carpet on its floor at the rate of INR 90.50/m2?
Option 1: INR 6,516
Option 2: INR 7,240
Option 3: INR 5,430
Option 4: INR 5,970
Question : A field is in the form of a circle. The cost of fencing around it at INR 12 per metre is INR 2,640. What is the area (in m2) of the field? (Take $\pi=\frac{22}{7}$)
Option 1: 1,925 m2
Option 2: 3,850 m2
Option 3: 2,772 m2
Option 4: 5,544 m2
Question : The internal length, breadth, and height of a cuboidal room are 12 m, 8 m, and 10 m, respectively. The total cost (in INR) of whitewashing only all four walls of the room at the cost of INR 25 per m2, is:
Option 1: 12,600
Option 2: 10,000
Option 3: 11,400
Option 4: 18,000
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