Question : The sides of $\triangle$ABC are 10 cm, 10.5 cm and 14.5 cm. What is the radius of its circumcircle?
Option 1: 5 cm
Option 2: 7.5 cm
Option 3: 5.25 cm
Option 4: 7.25 cm
Correct Answer: 7.25 cm
Solution : The sides of $\triangle$ABC are 10 cm, 10.5 cm and 14.5 cm. Now, $10.5^2 + 10^2$ $= 110.25 + 100$ $= 210.25 = 14.5^2$ So, the triangle is a right-angled triangle. Now, in a right-angled triangle, Circum radius of the triangle = $\frac{\text{Hypotenuse}}{2}$ = $\frac{14.5}{2}$ = 7.25 cm Hence, the correct answer is 7.25 cm.
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Question : In $\triangle$PQR, $\angle$ PQR = $90^{\circ}$, PQ = 5 cm and QR = 12 cm. What is the radius (in cm) of the circumcircle of $\triangle$PQR?
Option 1: 6.5
Option 2: 7.5
Option 3: 13
Option 4: 15
Question : If AB = 5 cm, AC = 12 cm, and AB$\perp$ AC, then the radius of the circumcircle of $\triangle ABC$ is:
Option 1: 6.5 cm
Option 2: 6 cm
Option 3: 5 cm
Option 4: 7 cm
Question : In $\triangle$ ABC, $\angle$ BCA = $90^{\circ}$, AC = 24 cm and BC = 10 cm. What is the radius (in cm) of the circumcircle of $\triangle$ ABC?
Option 1: 12.5
Option 2: 13
Option 3: 25
Option 4: 26
Question : The ratio of the total surface area and volume of a sphere is 2 : 7. Its radius is:
Option 1: 7.5 cm
Option 2: 10.5 cm
Option 3: 10 cm
Question : ABC is a right-angled triangle with AB = 6 cm and BC = 8 cm. A circle with centre O has been inscribed inside $\triangle ABC$. The radius of the circle is:
Option 1: 1 cm
Option 2: 2 cm
Option 3: 3 cm
Option 4: 4 cm
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