111 Views

The speed of the solid sphere after rolling down an inclined plane of length 6m and angle 30 from rest without sliding is


hemanth gm 6th Feb, 2020
Answer (1)
Pratyay Islam 10th Mar, 2020

Hello Student,

These questions can be easily solved using work energy theorem,

Which States : Work done by external torque on rotating a body is equal to change in rotational kinetic energy.

Now ,

Mgsin(x)*R = I(alpha) = (Mr^2 + Mk^2)a/R

Using the above equation we can derive the following :

Acceleration = gsin(x)/1+(k^2/r^2)

Velocity = {2gh/1+(k^2/r^2)}^1/2

[x = angle of inclination . h = height from which sphere starts rolling , k= radius of gyration , r = radius of the sphere , alpha = angular acceleration]

Velocity can be found out using the above formula.

Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida M.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida BBA Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
VIT Bhopal University | B.Arc...
Apply
Mark presence in the Modern Architectural field with Bachelor of Architecture | Highest CTC : 70 LPA | Accepts NATA Score
New Horizon College BBA Admis...
Apply
UG Admissions 2026 open| NAAC ‘A’ grade | Merit-based Scholarships available.
VIT Bhopal University | Integ...
Apply
Integrated M.Tech admissions open @ VIT Bhopal University | Highest CTC 70 LPA | Application Closing Soon | Apply now
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books