Question : The sum of a non-zero number and twice its reciprocal is $\frac{33}{4}$. Find the number.
Option 1: 9
Option 2: 10
Option 3: 11
Option 4: 8
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Correct Answer: 8
Solution : Let the non-zero integer be $x$. Given: The sum of a non-zero number and twice its reciprocal is $\frac{33}{4}$. $\Rightarrow x+\frac{2}{x}=\frac{33}{4}$ $\Rightarrow 4x^2-33x+8=0$ $\Rightarrow 4x^2-32x-x+8=0$ $\Rightarrow 4x(x-8)-(x-8)=0$ $\Rightarrow (4x-1)(x-8)=0$ $\Rightarrow (4x-1)=0 \;or\;(x-8)=0$ $\therefore x=8, \frac{1}{4}$ Hence, the correct answer is 8.
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Question : If $\frac{21\cos A+3\sin A}{3\cos A+4\sin A}=2$, then find the value of cot A.
Option 1: $\frac{9}{11}$
Option 2: $\frac{11}{9}$
Option 3: $\frac{1}{3}$
Option 4: $\frac{11}{10}$
Question : If $(4 y-\frac{4}{y})=13$, find the value of $(y^2+\frac{1}{y^2})$.
Option 1: $12 \frac{11}{16}$
Option 2: $10 \frac{9}{16}$
Option 3: $12 \frac{9}{16}$
Option 4: $8 \frac{9}{16}$
Question : A sum of Rs.10 is lent by a child to his friend to be returned in 11 monthly instalments of Re.1 each, the interest being simple. The rate of interest is:
Option 1: $11 \frac{9}{11} \%$
Option 2: $21 \frac{9}{11} \%$
Option 3: $10 \frac{2}{11} \%$
Option 4: $9 \frac{1}{11} \%$
Question : Choose the option in which the numbers are in the correct ascending order.
Option 1: $\frac{4}{5}, \frac{2}{3}, \frac{1}{11}$ and $\frac{2}{9}$
Option 2: $\frac{1}{11}, \frac{2}{9}, \frac{2}{3}$ and $\frac{4}{5}$
Option 3: $\frac{2}{9}, \frac{1}{11}, \frac{4}{5}$ and $\frac{2}{3}$
Option 4: $\frac{2}{3}, \frac{4}{5}, \frac{1}{11}$ and $\frac{2}{9}$
Question : The reciprocal of the sum of the reciprocals of $\frac{2}{9}$ and $\frac{7}{10}$ is:
Option 1: $\frac{14}{83}$
Option 2: $\frac{83}{14}$
Option 3: $\frac{90}{83}$
Option 4: $\frac{83}{90}$
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