Question : The sum of interior angles of a regular polygon is $1440^{\circ}$. The number of sides of the polygon is:
Option 1: 10
Option 2: 12
Option 3: 6
Option 4: 8
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Correct Answer: 10
Solution : Sum of all angles = $1440^{\circ}$ Let the number of sides of the polygon be $n$. ⇒ $1440^{\circ}$ = $(n-2)×180^{\circ}$ ⇒ $(n-2)$ = $\frac{1440}{180}$ ⇒ $(n-2)$ = $8$ ⇒ $n$ = $2+8$ = $10$ Hence, the correct answer is 10.
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Question : If the sum of all interior angles of a regular polygon is 14 right angles, then its number of sides is:
Option 1: 8
Option 2: 9
Option 3: 7
Option 4: 6
Question : The sum of all internal angles of a regular polygon whose one external angle is $20^\circ$ is:
Option 1: $6400^\circ$
Option 2: $3200^\circ$
Option 3: $2880^\circ$
Option 4: $1440^\circ$
Question : The measure of each interior angle of a regular polygon with 8 sides is:
Option 1: $135^{\circ}$
Option 2: $120^{\circ}$
Option 3: $100^{\circ}$
Option 4: $45^{\circ}$
Question : In a regular polygon if one of its internal angles is greater than the external angle by $132^\circ$, then the number of sides of the polygon is:
Option 1: $14$
Option 2: $12$
Option 3: $15$
Option 4: $16$
Question : If the sides of a triangle are extended on both sides then the sum of the exterior angles formed on both sides is:
Option 1: $360^{\circ}$
Option 2: $540^{\circ}$
Option 3: $720^{\circ}$
Option 4: $180^{\circ}$
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