Question : The sum of squares of 3 consecutive positive numbers is 365. The sum of the numbers is:
Option 1: 30
Option 2: 33
Option 3: 36
Option 4: 45
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Correct Answer: 33
Solution : Let the numbers be $n–1, n$ and $n+1$. $(n–1)^{2} + (n)^{2} + (n+1)^{2} = 365$ or, $n^2 – 2n+1+n^2+n^2+2n+1 = 365$ or, $3n^2 = 365–2$ or, $3n^2 = 363$ or, $n^2 = 121$ or, $n = 11$ So, 10, 11 and 12 are the numbers. Their sum is (10 + 11 + 12) = 33 Hence, the correct answer is 33.
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Question : The sum of the squares of 3 consecutive positive numbers is 365. The sum of the numbers is:
Question : Three numbers are in the ratio of 1 : 2 : 3. The product of the three numbers is 1296. What is the sum of the three numbers?
Option 1: 36
Option 2: 30
Option 3: 72
Option 4: 24
Question : The product of two positive numbers is 240. If the ratio of the two numbers is 3 : 5, then what is the sum of the two numbers?
Option 1: 46
Option 2: 45
Option 3: 32
Option 4: 42
Question : Three positive numbers are in the proportion of 2 : 3 : 5. If the sum of their squares is 342, then find the largest number.
Option 1: 35
Option 2: 55
Option 3: 15
Option 4: 25
Question : The average of 4 consecutive numbers is 35.5. Find the highest number among these numbers.
Option 1: 37
Option 2: 36
Option 3: 40
Option 4: 39
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