Question : The sum of the squares of 3 consecutive positive numbers is 365. The sum of the numbers is:
Option 1: 30
Option 2: 33
Option 3: 36
Option 4: 45
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Correct Answer: 33
Solution : Let the consecutive numbers be (x – 1), x and (x + 1). According to the question, (x–1)2 + x2 + (x+1)2 = 365 ⇒ (x2 – 2x + 1) + x2 + (x2 + 2x + 1) = 365 ⇒ 3x2 = 365 – 2 ⇒ 3x2 = 363 ⇒ x2 = 121 ⇒ x = 11 So, the numbers are 10, 11 and 12. The sum of the numbers = 10 + 11 + 12 = 33 Hence, the correct answer is 33.
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Question : The sum of squares of 3 consecutive positive numbers is 365. The sum of the numbers is:
Question : Three numbers are in the ratio of 1 : 2 : 3. The product of the three numbers is 1296. What is the sum of the three numbers?
Option 1: 36
Option 2: 30
Option 3: 72
Option 4: 24
Question : The product of two positive numbers is 240. If the ratio of the two numbers is 3 : 5, then what is the sum of the two numbers?
Option 1: 46
Option 2: 45
Option 3: 32
Option 4: 42
Question : Three positive numbers are in the proportion of 2 : 3 : 5. If the sum of their squares is 342, then find the largest number.
Option 1: 35
Option 2: 55
Option 3: 15
Option 4: 25
Question : The average of 4 consecutive numbers is 35.5. Find the highest number among these numbers.
Option 1: 37
Option 2: 36
Option 3: 40
Option 4: 39
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