Question : The upper part of a tree broken at a certain height makes an angle of 60° with the ground at a distance of 10 metres from its foot. The original height of the tree was:
Option 1: $20\sqrt{3}$ metres
Option 2: $10{\sqrt3}$ metres
Option 3: $10\left (2+{\sqrt3} \right)$ metres
Option 4: $10\left (2-{\sqrt3}\right)$ metres
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Correct Answer: $10\left (2+{\sqrt3} \right)$ metres
Solution : Let CD be the height of the tree and it breaks from the point B which touches the ground at A. As AB = BD, the total height of the tree CD = BC + AB In $\triangle ABC$, $\tan 60°=\frac{BC}{10}$ ⇒ $\sqrt{3}=\frac{BC}{10}$ ⇒ $BC=10\sqrt{3}$ metres Again in $\triangle ABC$, $(AB)^{2}=(BC)^{2}+(AC)^{2}$ ⇒ $(AB)^{2}=(10\sqrt{3})^{2}+(10)^{2}$ ⇒ $(AB)^{2}=300+100$ ⇒ $(AB)^{2}=400$ ⇒ $AB=20$ metres Original Height of the tree $=AB+BC$ $=20+10\sqrt{3}$ $=10(2+\sqrt{3})$ metres Hence, the correct answer is $10(2+\sqrt{3})$ metres.
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Question : The top of a broken tree touches the ground at a distance of 15 metres from its base. If the tree is broken at a height of 8 metres from the ground, then the actual height of the tree is:
Option 1: 17 metres
Option 2: 20 metres
Option 3: 25 metres
Option 4: 30 metres
Question : The angle of depression of two ships from the top of a lighthouse is $60^{\circ}$ and $45^{\circ}$ towards the east. If the ships are 300 metres apart, the height of the lighthouse (in metres) is:
Option 1: $200\left ( 3+\sqrt{3} \right )$
Option 2: $250\left ( 3+{\sqrt3} \right )$
Option 3: $150\left (3 +{\sqrt3} \right)$
Option 4: $160 \left (3+{\sqrt3} \right)$
Question : The shadow of a tower when the angle of elevation of the sun is 45°, is found to be 10 metres longer than when it was 60°. The height of the tower is:
Option 1: $5\sqrt{3}-1$ metres
Option 2: $5(3+\sqrt{3})$ metres
Option 3: $10(\sqrt{3}-1)$ metres
Option 4: $10(\sqrt{3}+1)$ metres
Question : From the top of a 20 metres high building, the angle of elevation from the top of a tower is 60° and the angle of depression of its foot is at 45°, then the height of the tower is: $(\sqrt{3} = 1.732)$
Option 1: 45.46 metres
Option 2: 45.64 metres
Option 3: 54.64 metres
Option 4: 54.46 metres
Question : On the ground, there is a vertical tower with a flagpole on its top. At a point 9 metres away from the foot of the tower, the angles of elevation of the top and bottom of the flagpole are 60° and 30°, respectively. The height of the flagpole is:
Option 1: $5\sqrt{3}$ metres
Option 2: $6\sqrt{3}$ metres
Option 3: $6\sqrt{2}$ metres
Option 4: $6\sqrt{5}$ metres
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