Question : The value of (1 + cot A – cosec A)(1 + tan A + sec A) – 1 is:
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 0
Correct Answer: 1
Solution : $(1+ \cot A – \operatorname{cosec} A)(1 + \tan A + \sec A) – 1$ $=(1+\frac{\cos A}{\sin A}-\frac{1}{\sin A})(1+\frac{\sin A}{\cos A}+\frac{1}{\cos A})-1$ $=(\frac{\sin A+\cos A-1}{\sin A})(\frac{\cos A+\sin A+1}{\cos A})-1$ $=\frac{(\sin A+\cos A)^2-1^2}{\sin A \cos A}-1$ $=\frac{\sin ^2 A +\cos^2 A+2\sin A \cos A-1}{\sin A \cos A}-1$ $=\frac{1+2\sin A \cos A-1}{\sin A \cos A}-1$ $=\frac{2\sin A \cos A}{\sin A \cos A}-1$ $=2-1$ $=1$ Hence, the correct answer is 1.
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Question : The value of $\sqrt{\frac{1+\sin A}{1-\sin A}}$ is:
Option 1: $\sec A-\tan A$
Option 2: $\operatorname{cosec} A+\cot A$
Option 3: $\sec A+\tan A$
Option 4: $\operatorname{cosec} A-\cot A$
Question : Find the value of $\left(\tan ^2 \theta+\tan ^4 \theta\right)$.
Option 1: $\cot ^2 \theta-\tan ^2 \theta$
Option 2: $\ {\sec}^4 \theta-\ {\sec}^2 \theta$
Option 3: $\ {\sec}^4 \theta-\ {\sec}^4 \theta$
Option 4: $ \ {\sec}^4 \theta+\ {\sec}^2 \theta$
Question : The value of $\frac{\sin A}{\cot A+\operatorname{cosec} A}-\frac{\sin A}{\cot A-\operatorname{cosec} A}+1$ is:
Option 1: $\frac{1}{2}$
Option 2: $3$
Option 3: $0$
Option 4: $2$
Question : The value of $(\operatorname{cosec}A+\cot A)(1 - \cos A)$ is:
Option 1: $\cos A$
Option 2: $\tan A$
Option 3: $\cot A$
Option 4: $\sin A$
Question : What is the value of $\frac{\sin (A+B)}{\sin A \cos B}$?
Option 1: $1 + \cot A \tan B$
Option 2: $1 + \tan A \cot B$
Option 3: $1 – \sin A \cos B$
Option 4: $1 − \cot A \tan B$
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