Question : The value of $\sqrt{2\sqrt[3]{4\sqrt{2\sqrt[3]{4\sqrt{2\sqrt[3]{4.......}}}}}}$ is:
Option 1: 2
Option 2: $2^{2}$
Option 3: $2^{3}$
Option 4: $2^{5}$
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Correct Answer: 2
Solution : Let $x=\sqrt{2\sqrt[3]{4\sqrt{2\sqrt[3]{4\sqrt{2\sqrt[3]{4.......}}}}}}$ By squaring both sides, we get, $⇒x^{2} =2×\sqrt[3]{{4×x}}$ By cubing both sides, we get: $⇒x^{6}=8×4x$ $⇒x^{5}=32=2^{5}$ $\therefore x=2$ Hence, the correct answer is 2.
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Question : If $x=1+\sqrt{2}+\sqrt{3}$, then the value of $(2x^4-8x^3-5x^2+26x-28)$ is:
Option 1: $2\sqrt{2}$
Option 2: $3\sqrt{3}$
Option 3: $5\sqrt{5}$
Option 4: $6\sqrt{6}$
Question : If $x=\frac{\sqrt{5}+1}{\sqrt{5}-1}$ and $y=\frac{\sqrt{5}-1}{\sqrt{5}+1}$, then the value of $\frac{x^{2}+xy+y^{2}}{x^{2}-xy+y^{2}}$ is:
Option 1: $\frac{3}{4}$
Option 2: $\frac{4}{3}$
Option 3: $\frac{3}{5}$
Option 4: $\frac{5}{3}$
Question : If $\frac{\sqrt{5+x}+\sqrt{5-x}}{\sqrt{5+x}-\sqrt{5-x}}=3$, what is the value of $x$?
Option 1: $\frac{5}{2}$
Option 2: $\frac{25}{3}$
Option 3: $4$
Option 4: $3$
Question : If $\left(x^2+\frac{1}{x^2}\right)=7$, and $0<x<1$, find the value of $x^2-\frac{1}{x^2}$.
Option 1: $3 \sqrt{5}$
Option 2: $4 \sqrt{5}$
Option 3: $-4\sqrt{3}$
Option 4: $-3\sqrt{5}$
Question : What is the value of $\sin 30^{\circ}+\cos 30^{\circ}+\tan 30^{\circ}$?
Option 1: $\frac{5+\sqrt{3}}{2 \sqrt{3}}$
Option 2: $\frac{5-\sqrt{3}}{2 \sqrt{3}}$
Option 3: $\frac{5+\sqrt{3}}{\sqrt{3}}$
Option 4: $\frac{5-\sqrt{3}}{\sqrt{3}}$
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