Question : The value of $\text{cosec}^{2}\: 18°-\frac{1}{\cot^{2}72°}$ is:
Option 1: $\frac{1}{\sqrt3}$
Option 2: $\frac{\sqrt2}{3}$
Option 3: $\frac{1}{2}$
Option 4: $1$
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Correct Answer: $1$
Solution : $\text{cosec}^{2}\: 18°-\frac{1}{\cot^{2}72°}$ $= \text{cosec}^{2}\: 18° - \frac{1}{\cot^{2}(90-18)°}$ $= \text{cosec}^{2}\: 18° - \frac{1}{\tan^{2}18°}$ $= \text{cosec}^{2}\: 18° - \cot^{2}18°$ $= 1$ Hence, the correct answer is $1$.
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Question : $\triangle$XYZ is right angled at Y. If $\angle$X = 60°, then find the value of $(\sec Z+\frac{2}{\sqrt3})$.
Option 1: $\frac{4}{\sqrt3}$
Option 2: $\frac{\sqrt2+2}{2\sqrt2}$
Option 3: $\frac{7}{2\sqrt3}$
Option 4: $\frac{4}{2\sqrt3}$
Question : The value of $\cot 13° \cot 27° \cot 60° \cot 63° \cot 77°$ is:
Option 1: $\frac{1}{\sqrt{3}}$
Option 2: $0$
Option 3: $\sqrt{3}$
Question : If $\theta$ is a positive acute angles and $\operatorname{cosec}\theta =\sqrt{3}$, then the value of $\cot \theta -\operatorname{cosec}\theta$ is:
Option 1: $\sqrt2-\sqrt3$
Option 2: $\frac{\sqrt{2}(3+\sqrt{3})}{3}$
Option 3: $\frac{\sqrt{2}(3-\sqrt{3})}{3}$
Option 4: $\frac{3\sqrt{2}+\sqrt{3}}{3}$
Question : What is the value of $\frac{\cot \theta+\operatorname{cosec} \theta-1}{\cot \theta-\operatorname{cosec} \theta+1}$?
Option 1: $2 \sec \theta$
Option 2: $2 \operatorname{cosec} \theta$
Option 3: $2 \cot \theta$
Option 4: $\operatorname{cosec} \theta+\cot \theta$
Question : The value of $\cos \ 0°+\cos\ 1°+\cos\ 2°......\cos\ 180°$ is:
Option 1: $0$
Option 2: $1$
Option 3: $\frac{\sqrt3}{2}$
Option 4: $\frac{1}{2}$
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