Question : The value of $\frac{1+\sin A}{\cos A}+\frac{\cos A}{1+\sin A}$ is:
Option 1: $2 \sec A$
Option 2: $2 \operatorname{cosec} A$
Option 3: $ \sec A$
Option 4: $ \operatorname{cosec} A$
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Correct Answer: $2 \sec A$
Solution : Consider $\frac{1+\sin A}{\cos A}+\frac{\cos A}{1+\sin A}$ = $\frac{(1+\sin A)(1+\sin A)+\cos^2A}{\cos A(1+\sin A)}$ = $\frac{1+\sin^2A+2\sin A + cos^2A}{\cos A(1+\sin A)}$ = $\frac{1+1+2\sin A}{\cos A(1+\sin A)}$ [Using $\sin^2A+\cos^2A=1$] = $\frac{2+2\sin A}{\cos A(1+\sin A)}$ = $\frac{2(1+\sin A)}{\cos A(1+\sin A)}$ = $\frac{2}{\cos A}$ = $2\sec A$ Hence, the correct answer is $2\sec A$.
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Question : What is the value of the expression: $\sin A(1+\frac{\sin A}{\cos A})+\cos A(1+\frac{\cos A}{\sin A})$?
Option 1: $\sec A+\operatorname{cosec}A$
Option 2: $\sin \mathrm{A}+\cos \mathrm{A}$
Option 3: $\sin \mathrm{A}-\cos \mathrm{A}$
Option 4: $\sec \mathrm{A}-\operatorname{cosec} \mathrm{A}$
Question : What is the value of $\sqrt{\frac{\operatorname{cosec} A+1}{\operatorname{cosec} A-1}}+\sqrt{\frac{\operatorname{cosec} A-1}{\operatorname{cosec} A+1}}$?
Option 1: $2 \cos A$
Option 2: $\sec A$
Option 3: $2\cos A$
Option 4: $2 \sec A$
Question : If $\frac{\sin \theta-\cos \theta}{\sin \theta+\cos \theta}=\frac{4}{5}$, then the value of $\frac{\operatorname{cosec}^2 \theta}{2-\operatorname{cosec}^2 \theta}$ is:
Option 1: $\frac{16}{25}$
Option 2: $\frac{40}{41}$
Option 3: $\frac{41}{40}$
Option 4: $\frac{31}{30}$
Question : If $\sin \theta+\cos \theta=\frac{1}{29}$, then find the value of $\frac{\operatorname{sin} \theta+\operatorname{cos} \theta}{\operatorname{sin} \theta-\operatorname{cos} \theta}$.
Option 1: $\frac{1}{41}$
Option 2: $\frac{43}{29}$
Option 3: $\frac{41}{29}$
Option 4: $\frac{1}{43}$
Question : What is the value of $\frac{1+\tan A}{\operatorname{cosec} A}+\frac{1+\cot A}{\sec A}$?
Option 1: $2\sec^2A$
Option 2: $\sec \mathrm{A} - \mathrm{cosec A}$
Option 3: $\sec \mathrm{A} + \mathrm{cosec A}$
Option 4: $2 \;\mathrm{cosec^2 A}$
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