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there are 4 5 and 6 points on the parallel and coplanar lines if no set of 4 or more points is cyclic and no set of 3 points lying on distinct lines is collinear,then the no.of circles passing through exactly 3 points is.


V.sri swetha naga sai 12th Apr, 2022
Answer (1)
pri111nah 12th Apr, 2022

Hi,

It's mentioned that no more than 4 points can lie on the circle of the circle cannot pass through more than a set of four points.

So, it's obvious that from the parallel lines only one point can be included. Hence, here are the following combinations which can be found-

Case I: 4C1* 5C1*6C2

Case II: 4C1* 5C2*6C1

Case III: 5C2* 6C2

Case IV: 5C3* 6C1

Case V: 6C3* 5C1


Hope this helpful.

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