Three forces F1=2i+j-kN F2=2i+3j-3kN F3=a(i+j-k)N act simultaneously on a particle. The value of 'a' so that particle may be in equilibrium is 1)4 2)-4 3)2 4)6

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Three forces F1=2i+j-kN F2=2i+3j-3kN F3=a(i+j-k)N act simultaneously on a particle. The value of 'a' so that particle may be in equilibrium is 1)4 2)-4 3)2 4)6

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mpujari465 17th Sep, 2020

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Answer (1)

G.Roshini 17th Sep, 2020

Hello,

In the question it is stated that to be in equilibrium .In equilibrium their sum should be equal to zero .

So F1+F2+F3=0

2i+j-k+2i+3j-3k+ai+aj-ak=0

(4+a)i+(4+a)j-(4+a)k=0i+0j+0k

If we compare on both the sides

a=-4

Hope this answers helps!

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