Hi Saloni! Below is the solution to your question:

When two dice are rolled simultaneously, each die has 6 possible outcomes.

Total possible outcomes

$6 \times 6 = 36$

Possible pairs whose sum is 5:

$(1,4), (2,3), (3,2), (4,1)$

Number of favorable outcomes $4$

Probability formula

$P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$

So, $P(\text{sum } = 5) = \frac{4}{36}$

Simplify the fraction:

$P = \frac{1}{9}$

Hope it helps you, thanks!