Question : Two medians AD and BE of $\triangle$ ABC intersect at G at right angles. If AD = 9 cm and BE = 6 cm, then the length of BD (in cm) is:
Option 1: 10
Option 2: 6
Option 3: 5
Option 4: 3
Correct Answer: 5
Solution : Given: AD = 9 cm BE = 6 cm $\angle$DGB = 90° Here, the point of intersection of its medians, G divides the median in the ratio 2:1. So, DG = $\frac{1}{3}×$AD = $\frac{1}{3}×9=3$ cm BG = $\frac{2}{3}×$BE = $\frac{2}{3}×6=4$ cm From Pythagoras theorem we know, BD2 = DG2 + BG2 ⇒ BD2 = $3^2+4^2=25$ $\therefore$ BD = $\sqrt{25}=5$ cm. Hence, the correct answer is 5 cm.
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Question : If two medians BE and CF of a triangle ABC, intersect each other at G and if BG = CG, $\angle$BGC = $120^{\circ}$, BC = 10 cm, then the area of the triangle ABC is:
Option 1: $50\sqrt{3}$ $cm^2$
Option 2: $60$ $cm^2$
Option 3: $25$ $cm^2$
Option 4: $25\sqrt{3}$ $cm^2$
Question : In $\Delta$ABC, D is the mid-point of BC and G is the centroid. If GD = 5 cm then the length of AD is:
Option 1: 10 cm
Option 2: 12 cm
Option 3: 15 cm
Option 4: 20 cm
Question : In $\triangle$ABC, D is the median from A to BC. AB = 6 cm, AC = 8 cm, and BC = 10 cm.The length of median AD (in cm) is:
Option 1: 4.5
Option 2: 5
Option 3: 4
Question : Let $\triangle ABC \sim \triangle RPQ$ and $\frac{{area}(\triangle {ABC})}{{area}(\triangle {PQR})}=\frac{4}{9}$. If AB = 3 cm, BC = 4 cm and AC = 5 cm, then RP (in cm) is equal to:
Option 1: 6
Option 3: 4.5
Option 4: 12
Question : If in a triangle ABC, BE and CF are two medians perpendicular to each other and if AB = 19 cm and AC = 22 cm then the length of BC is:
Option 1: 19.5 cm
Option 2: 26 cm
Option 3: 20.5 cm
Option 4: 13 cm
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