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two particles are projected horizontally from the same elevated positions in opposite directions


Ramarao 26th Nov, 2019
Answer (1)
ADITYA KUMAR Student Expert 26th Nov, 2019
Hello there!

Greetings!

Although you haven't completed your question but I guess the question is asking to find the time when the two velocities are at 90 degree.

Now , to solve the problem let ( 3, v1) be first velocity and (-4,v2) be second velocity

Then,

V1 = v2= get = 10t

(3,10t) * (-4,10t) =0

-12 + 100t^2 = 0

t = (0.12)^1/2s i.e root 0.12 s.


Thankyou

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