565 Views
two particles are projected horizontally from the same elevated positions in opposite directions
Answer (1)
Greetings!
Although you haven't completed your question but I guess the question is asking to find the time when the two velocities are at 90 degree.
Now , to solve the problem let ( 3, v1) be first velocity and (-4,v2) be second velocity
Then,
V1 = v2= get = 10t
(3,10t) * (-4,10t) =0
-12 + 100t^2 = 0
t = (0.12)^1/2s i.e root 0.12 s.
Thankyou
Related Questions
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
XAT- Xavier Aptitude Test 2026
Apply
75+ years of legacy | #1 Entrance Exam | Score accepted by 250+ BSchools | Apply now
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
UPES MBA Admissions 2025
Apply
Ranked #41 amongst institutions in Management by NIRF | 100% Placement | Last Date to Apply: 15th July