203 Views

using Gauss law obtain in the expression for electric field intensity at a point outside a charged hollow sphere


Puja 1st May, 2020
Answer (1)
Tushar Karmakar 10th May, 2020

Let, R be the radius of the shell and Q be the charge uniformly distributed on the surface.

i) For a point outside the shell :

E×4pi r^2 = Qen/epsilon

From this equation you can easily find the equation of electric field outside the hollow sphere. But inside the hollow sphere there is no enclosed charge present so E=0 inside the sphere.


Related Questions

Amity University-Noida Law Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
RV University, Bangalore | La...
Apply
Excellent curriculum; an impressive range of electives, besides core law courses. Up to 100% merit scholarship on a first-come, first-served basis
BML Munjal University Law Adm...
Apply
Approved by Bar Council of India | 100% Scholarship | Accepts CLAT Scores | Applications Closing Soon!
UPES Integrated LLB Admission...
Apply
Last Date to Apply: 25th Feb | Ranked #18 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS Rankings | 16 L...
VIT Chennai Law Admissions 2026
Apply
#14 in India by NIRF Ranking | NAAC A++ accredited | Approved by BCI | Scholarships Available
NMIMS-Law Aptitude Test 2026
Apply
Admissions open for B.A.LL.B.(Hons.) & B.B.A.LL.B (Hons.) via NLAT @ NMIMS University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books